函数式子化简1-(sin^6∝+cos^6∝)原式=1-(sin^2∝+cos^2∝)(sin^4∝-sin^2∝*cos^2∝+cos^∝)式子中这一步是怎样得来的?(sin^4∝-sin^2∝*cos^2∝+cos^∝)
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 10:11:05
x){ھ
O?];iϴu(̋3{1W;9xi|:[C]
L Y09-XH
Ē';־?Ɏgk>YC߳۟lZ1&H8]D J/|ui;Nyںhu*⌵+m5*+55*t+*F@$Al<۴唙4B
函数式子化简1-(sin^6∝+cos^6∝)原式=1-(sin^2∝+cos^2∝)(sin^4∝-sin^2∝*cos^2∝+cos^∝)式子中这一步是怎样得来的?(sin^4∝-sin^2∝*cos^2∝+cos^∝)
函数式子化简
1-(sin^6∝+cos^6∝)
原式=1-(sin^2∝+cos^2∝)(sin^4∝-sin^2∝*cos^2∝+cos^∝)
式子中这一步是怎样得来的?
(sin^4∝-sin^2∝*cos^2∝+cos^∝)
函数式子化简1-(sin^6∝+cos^6∝)原式=1-(sin^2∝+cos^2∝)(sin^4∝-sin^2∝*cos^2∝+cos^∝)式子中这一步是怎样得来的?(sin^4∝-sin^2∝*cos^2∝+cos^∝)
立方和公式阿,x^3+y^3=(x+y)(x^2-xy+y^2)
没错!!!
函数式子化简1-(sin^6∝+cos^6∝)原式=1-(sin^2∝+cos^2∝)(sin^4∝-sin^2∝*cos^2∝+cos^∝)式子中这一步是怎样得来的?(sin^4∝-sin^2∝*cos^2∝+cos^∝)
化简式子 证明等式化简1.cos(90+a)+sin(180-a)-sin(180+a)-sin(-a)证明1.sin(a+b)/cosacosb=tana+tanb2.sin(a+b)cos(a-b)=sinacosa+sinbcosb
函数fx=cos(2x-π/3)+cos(2x+π/6)这个式子怎么化简
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3cosπ/4cosπ/3-sinπ/4sinπ/3
已知函数f(x)=sin^4x+cos^2x+1/4sin2xcos2x(x∈R)则f(x)化简的到式子是?
1+sin∝cos∝如何化成与tan有关的式子?
化简下列式子 cos(pai/4+a)+sin(pai/4+a)哥哥姐姐的详解
函数式根号1+sin(π-2)cos(π+2)化简的结果是
函数cos sin
(1-sin^6 a-cos^6 a)/(1-sin^4 a-cos^4 a)的化简结果
1-cos^6(a)-sin^6(a)化简得3sin^(a)cos^(a)的详细过程!
已知函数f(x)=sin(x+π/6)cos(x+π/6)如何把这种函数化简
sin x{sin x +cos x}+cos x{cos x +cos x} 化成正弦函数或余弦函数怎么化?
matlab怎么样化简三角函数?cos(x)*cos(y+z)+cos(x)+2cos(y+z)-sin(x)sin(y+z)这个式子在MATLAB中如何化简
cos(n+1)x=cos(nx)cosx-sin(nx)sinx这个式子是怎推出来的?
(1-sin^6 a-cos^6 a)/(sin^2 a-sin^4 a)的化简结果,
已知函数f(x)=cos²(x+π/6)-sin²(x+π/6)我就想知道这个式子是怎样展开的,麻烦详细点咯
化简一个式子cos²(-a)-tan(360°+a)/sin(-a)我的答案有点怪