在三角形ABC中,角CAB,角CBA的平分线交于点D,DE//AC交于BC于E,DF//BC交于AC于点F,求证四边形DECF为菱形
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![在三角形ABC中,角CAB,角CBA的平分线交于点D,DE//AC交于BC于E,DF//BC交于AC于点F,求证四边形DECF为菱形](/uploads/image/z/1647073-1-3.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92CAB%2C%E8%A7%92CBA%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E4%BA%8E%E7%82%B9D%2CDE%2F%2FAC%E4%BA%A4%E4%BA%8EBC%E4%BA%8EE%2CDF%2F%2FBC%E4%BA%A4%E4%BA%8EAC%E4%BA%8E%E7%82%B9F%2C%E6%B1%82%E8%AF%81%E5%9B%9B%E8%BE%B9%E5%BD%A2DECF%E4%B8%BA%E8%8F%B1%E5%BD%A2)
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