已知1-tanα/1+tanα=4+√3,则cot(π/4+α)的值为?步骤1-tanα/1+tanα=tan(π/4-α)=4+√3,cot(π/4+α)=cot[π/2-(π/4-α)]=tan[π/2-(π/4-α)]=4+√3第二步步骤再具体解释下
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![已知1-tanα/1+tanα=4+√3,则cot(π/4+α)的值为?步骤1-tanα/1+tanα=tan(π/4-α)=4+√3,cot(π/4+α)=cot[π/2-(π/4-α)]=tan[π/2-(π/4-α)]=4+√3第二步步骤再具体解释下](/uploads/image/z/1649363-59-3.jpg?t=%E5%B7%B2%E7%9F%A51%EF%BC%8Dtan%CE%B1%EF%BC%8F1%EF%BC%8Btan%CE%B1%EF%BC%9D4%EF%BC%8B%E2%88%9A3%2C%E5%88%99cot%28%CF%80%EF%BC%8F4%EF%BC%8B%CE%B1%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%BA%3F%E6%AD%A5%E9%AA%A41-tan%CE%B1%2F1%2Btan%CE%B1%3Dtan%28%CF%80%2F4-%CE%B1%29%3D4%EF%BC%8B%E2%88%9A3%2Ccot%28%CF%80%EF%BC%8F4%EF%BC%8B%CE%B1%EF%BC%89%3Dcot%5B%CF%80%2F2-%28%CF%80%2F4-%CE%B1%29%5D%3Dtan%5B%CF%80%2F2-%28%CF%80%2F4-%CE%B1%29%5D%3D4%EF%BC%8B%E2%88%9A3%E7%AC%AC%E4%BA%8C%E6%AD%A5%E6%AD%A5%E9%AA%A4%E5%86%8D%E5%85%B7%E4%BD%93%E8%A7%A3%E9%87%8A%E4%B8%8B)
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