概率论依概率收敛问题设总体X~π(2),X1,X2.Xn是来自总体X的样本,则当n→∞时,1/n ∑Xi^2依概率收敛于()注:∑的上面是n,下面是i=1.设总体X~N(μ,σ^2),X1,X2.Xn是来自总体X的样本,X平均数为样本
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![概率论依概率收敛问题设总体X~π(2),X1,X2.Xn是来自总体X的样本,则当n→∞时,1/n ∑Xi^2依概率收敛于()注:∑的上面是n,下面是i=1.设总体X~N(μ,σ^2),X1,X2.Xn是来自总体X的样本,X平均数为样本](/uploads/image/z/1649531-11-1.jpg?t=%E6%A6%82%E7%8E%87%E8%AE%BA%E4%BE%9D%E6%A6%82%E7%8E%87%E6%94%B6%E6%95%9B%E9%97%AE%E9%A2%98%E8%AE%BE%E6%80%BB%E4%BD%93X%7E%CF%80%282%29%2CX1%2CX2.Xn%E6%98%AF%E6%9D%A5%E8%87%AA%E6%80%BB%E4%BD%93X%E7%9A%84%E6%A0%B7%E6%9C%AC%2C%E5%88%99%E5%BD%93n%E2%86%92%E2%88%9E%E6%97%B6%2C1%2Fn+%E2%88%91Xi%5E2%E4%BE%9D%E6%A6%82%E7%8E%87%E6%94%B6%E6%95%9B%E4%BA%8E%EF%BC%88%EF%BC%89%E6%B3%A8%EF%BC%9A%E2%88%91%E7%9A%84%E4%B8%8A%E9%9D%A2%E6%98%AFn%2C%E4%B8%8B%E9%9D%A2%E6%98%AFi%3D1.%E8%AE%BE%E6%80%BB%E4%BD%93X%7EN%EF%BC%88%CE%BC%2C%CF%83%5E2%EF%BC%89%2CX1%2CX2.Xn%E6%98%AF%E6%9D%A5%E8%87%AA%E6%80%BB%E4%BD%93X%E7%9A%84%E6%A0%B7%E6%9C%AC%2CX%E5%B9%B3%E5%9D%87%E6%95%B0%E4%B8%BA%E6%A0%B7%E6%9C%AC)
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