设{an}未等差数列,{bn}为等比数列,a1=b1=1,a2+a4=b3,b2b4=a3,分别求{an} ,{bn}前十项和S10,T10

设{an}未等差数列,{bn}为等比数列,a1=b1=1,a2+a4=b3,b2b4=a3,分别求{an} ,{bn}前十项和S10,T10 设{an}未等差数列,{bn}为等比数列,a1=b1=1,a2+a4=b3,b2b4=a3,分别求{an} ,{bn}前十项和S10,T10 设{an}未等差数列,{bn}为等比数列,a1=b1=1,a3+a5=b4,b2b3=a8,分别求{an} ,{bn}前十项和S10,T10 设数列an为等差数列,数列bn为等比数列若a1 设数列an为等差数列,数列bn为等比数列若a1 设数列(an)为等差数列,数列(bn)为等比数列,若a1 设{an}是等差数列,{bn}是等比数列,且0 如果数列{an}是等差数列,设bn=(1/2)^an,数列{bn}是等比数列吗? 设各项均为正数的数列{an}和{bn}满足:an,bn,an+1成等差数列,bn,an+1,bn+1等比数列且a1=1,b1=2,a2=3求通项an,bn 设各项均为正数的数列｛an}和｛bn}满足：an,bn,an+1成等差数列,bn,an+1,bn+1成等比数列,且a1=1,b1=2,a2=3,求通项an,bn 设数列{an}是等比数列,bn=an+an+1,问{bn}是否为等比数列 设An为正数等差数列 Bn为正数等比数列,则a1=b1 a21=b21 为什么 a11≥b11 一道数学题设an为等差数列,bn为等比数列,a1+b1=1,a2+a4=b3,分别求出an和bn的前10项和 已知等差数列{an}的前n项和为Sn,且a2=1,S11=33,设bn=(1/2)^an,证明｛bn}为等比数列 设数列{an}{bn}满足a1=b1=6 a2=b2=4 a3=b3=3若{an+1 - an}为等差数列.{bn+1 -bn}为等比数列.分别求{an}{bn}的通项公式. 设{an}为等差数列,且等比数列{bn}中有b1=a1^2,b2=a2^2,b3^2(a1 已知等差数列{an}的前四项和为10,且a2,a3,a7成等比数列.(1)求通项公式an.（2）设bn=2^an,求数列bn...已知等差数列{an}的前四项和为10,且a2,a3,a7成等比数列.(1)求通项公式an.（2）设bn=2^an,求数列bn的前n an的前n项和为Sn,-a1,sn,an+1成等差数列求an 2设bn=1-Sn问是否存在a1,使等差数列bn为等比数列求a1的值2）设bn=1-Sn问是否存在a1，使等差数列bn为等比数列求a1的值