多项式除法 是怎么运算的!y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))这个是怎么算的啊 y=x³/(x²-3x+2)y=(x+3)+(7x-6)/( (x-2)(x-1) )=x+3+8/(x-2)-1/(x-1)怎么算的?y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))
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![多项式除法 是怎么运算的!y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))这个是怎么算的啊 y=x³/(x²-3x+2)y=(x+3)+(7x-6)/( (x-2)(x-1) )=x+3+8/(x-2)-1/(x-1)怎么算的?y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))](/uploads/image/z/1963890-18-0.jpg?t=%E5%A4%9A%E9%A1%B9%E5%BC%8F%E9%99%A4%E6%B3%95+%E6%98%AF%E6%80%8E%E4%B9%88%E8%BF%90%E7%AE%97%E7%9A%84%21y%3D%28ax%2Bb%29%2F%28cx%2Bd%29+y%3Da%2Fc%2B%28bc-ad%29%2F%28c%26%23178%3B%29+%2A1%2F%28x%2B%28d%2Fc%29%29%E8%BF%99%E4%B8%AA%E6%98%AF%E6%80%8E%E4%B9%88%E7%AE%97%E7%9A%84%E5%95%8A+y%3Dx%26%23179%3B%2F%28x%26%23178%3B-3x%2B2%29y%3D%28x%2B3%29%2B%287x-6%29%2F%28+%28x-2%29%28x-1%29+%29%3Dx%2B3%2B8%2F%28x-2%29-1%2F%28x-1%29%E6%80%8E%E4%B9%88%E7%AE%97%E7%9A%84%3Fy%3D%28ax%2Bb%29%2F%28cx%2Bd%29+y%3Da%2Fc%2B%28bc-ad%29%2F%28c%26%23178%3B%29+%2A1%2F%28x%2B%28d%2Fc%29%29)
多项式除法 是怎么运算的!y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))这个是怎么算的啊 y=x³/(x²-3x+2)y=(x+3)+(7x-6)/( (x-2)(x-1) )=x+3+8/(x-2)-1/(x-1)怎么算的?y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))
多项式除法 是怎么运算的!
y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))这个是怎么算的啊 y=x³/(x²-3x+2)y=(x+3)+(7x-6)/( (x-2)(x-1) )=x+3+8/(x-2)-1/(x-1)怎么算的?
y=(ax+b)/(cx+d)
y=a/c+(bc-ad)/(c²) *1/(x+(d/c))
这个是怎么算的啊
y=x³/(x²-3x+2)
y=(x+3)+(7x-6)/( (x-2)(x-1) )=x+3+8/(x-2)-1/(x-1)
怎么算的?
多项式除法 是怎么运算的!y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))这个是怎么算的啊 y=x³/(x²-3x+2)y=(x+3)+(7x-6)/( (x-2)(x-1) )=x+3+8/(x-2)-1/(x-1)怎么算的?y=(ax+b)/(cx+d) y=a/c+(bc-ad)/(c²) *1/(x+(d/c))
y=a/c+(bc-ad)/(c²) *1/(x+(d/c))
=a/c+ (bc-ad)/[c(cx+d)]=[a(cx+d) + (bc-ad)]/[c(cx+d)]=[acx+ad)+ (bc-ad)]/[c(cx+d)]
=(ax+b)/(cx+d)
x+3+8/(x-2)-1/(x-1)
=x+3+[8(x-1)-(x-2)]/( (x-2)(x-1) )=(x+3)+(7x-6)/( (x-2)(x-1) )
(x+3)+(7x-6)/( (x-2)(x-1) )=[(x+3)(x-2)(x-1)+(7x-6)]/( (x-2)(x-1) )
=[(x+3)(x^2-3x+2)+7x-6]/(x²-3x+2)
=[x^3-3x^2+2x+3x^2-9x+6+7x-6]/(x²-3x+2)
=x³/(x²-3x+2)