log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少.
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log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少.
log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少.
log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少.
即log3 m=1og3 18 ,所以m=3.
用换底公式,换任一底都行.以10为底书写较简单.
log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少.
log3(4)·log4(8)·log8(m)=log4(16)则m=
设log3(4)*log4(8)*log8(m)=log4(16)那么m等于~
若log3 4*log4 8*log8 m=log4 16求m
log4 8-log8 4=?
化简log3(4)*log4(5)*log5(8)*log8(9)的结果是?
log3 4×log4 8×log8 a=log根号3 9,则a=
(log3^2 + log9^4)×(log4^3 + log8^3)
log3 4*log4 8*log8 m=log4 16,则m为[ ]其中3、4、8、4为底数.
log3^4乘log4^8乘log8^m=log4^2麻烦过程写清楚一点.谢谢、
若log3(4)×log4(8)×log8(m)=log4(16).则m等于?谢谢
log3^4*log4^8*log8^m=log4^2 求mlog8^3=p log3^5=q用pq表示lg5
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?..
(log4(3)+log8(3))*log3(2)
求值:(log4(3)+log8(3))(log3(2)+log3(4))-log2(64)
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9
若log3^5 log5^7 log7^x=log4^2 log6^4 log8^6,求x=?
log3 4×log4 8×log8 m=log4 16,则m=( )(注:3,4,8是底数)请写出详细过程,