等比数列an前n项和sn满足s1,s3,s2成等差数列,求sn
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等比数列an前n项和sn满足s1,s3,s2成等差数列,求sn
等比数列an前n项和sn满足s1,s3,s2成等差数列,求sn
等比数列an前n项和sn满足s1,s3,s2成等差数列,求sn
等比数列{an}中,前n项和为sn,已知S1,S3,S2成等差数列,求{an}的公比Q.已知a1-a3=3,求sn?
S1=a1
S2=a1(1+q)
S3=a1(1+q+q^2)
S1,S3,S2成等差数列
即
s3-s1=s2-s3
1+q+q^2-1=1+q-(1+q+q^2)
q^2+q=-q^2
q=0或-1/2
如果a1-a3=3
a1不等于a3
q不等于0,即q=-1/2
a1(1-1/4)=3
a1=4
所以Sn=4*(1-(-1/2)^n)/(3/2)=8*(1-(-1/2)^n)/3
S1=a1
S3=a1+a2+a3=a1+a1q+a1q²
S2=a1+a2=a1+a1q
2S3=S1+S3
所以a1q+2a1q²=0
等比则a1和q都不等于0
所以1+2q=0
q=-1/2
只能求到这里,不能求出具体的Sn
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