化简求值;(1-sin80°)/cos80°
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 02:10:09
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化简求值;(1-sin80°)/cos80°
化简求值;(1-sin80°)/cos80°
化简求值;(1-sin80°)/cos80°
1-sin80°)/cos80°
=(1-sin2*40°)/(cos2*40°)
=(1-2sin40°cos40°)/(2cos240°-1)
=(sin240°+cos240°-2sin40°cos40°)/(2cos240°-sin240°-cos240°)
=(cos40°-sin40°)2/(cos240°-sin240°)
=(cos40°-sin40°)2/(cos40°-sin40°)(cos40°+sin40°)
=(cos40°-sin40°)/(cos40°+sin40°)
化简求值;(1-sin80°)/cos80°
(2cos20°-sin10°)/sin80°化简求值
化简求值:2cosˆ210°-tan5°(1+cos10°)-2sin40°sin80°
化简求值(2sin80`-cos70`)/cos20`
化简求值:sin20° + sin40° - sin80°如何求值?公示和步骤写清楚
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
求值:[2sin50°+sin80°(1+√3tan10°)]/√2cos5°
求值:(2sin80°-cos70°)/cos20°
求值:1/sin10°-根号3/sin80°
求值:1/sin10°-√3/sin80°
化简根号1-sin80
求值[2sin50°+sin80°(1+√3tan10°)]/√(1+cos10°)
2(根号sin8-1)+根号下(2cos8+2)化简谢谢!
求值:sin10°sin50°sin70°sin80°
化简(1-sin80)/cos80
一道必修四数学题2sin50°+sin80°(1+根号3 tan10°)-----------------------------根号1+cos10°求值题.
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)