若a1\b1=a2\b2=……=an\bn(a1,a2,……an,b2,……bn都是正整数),求证:√a1b1+√a2b2+……√anbn=√(a1+a2+a3+a4+……+an)(b1+b2+b3+……+bn)
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![若a1\b1=a2\b2=……=an\bn(a1,a2,……an,b2,……bn都是正整数),求证:√a1b1+√a2b2+……√anbn=√(a1+a2+a3+a4+……+an)(b1+b2+b3+……+bn)](/uploads/image/z/2507298-42-8.jpg?t=%E8%8B%A5a1%5Cb1%3Da2%5Cb2%3D%E2%80%A6%E2%80%A6%3Dan%5Cbn%28a1%2Ca2%2C%E2%80%A6%E2%80%A6an%2Cb2%2C%E2%80%A6%E2%80%A6bn%E9%83%BD%E6%98%AF%E6%AD%A3%E6%95%B4%E6%95%B0%EF%BC%89%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E2%88%9Aa1b1%2B%E2%88%9Aa2b2%2B%E2%80%A6%E2%80%A6%E2%88%9Aanbn%3D%E2%88%9A%28a1%2Ba2%2Ba3%2Ba4%2B%E2%80%A6%E2%80%A6%2Ban%29%28b1%2Bb2%2Bb3%2B%E2%80%A6%E2%80%A6%2Bbn%29)
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