已知tan(π/4+α)=2,tanβ=1/2.⑴求tanα的值,⑵求sin(α+β)-2sinαcosβ/2sinαcosβ+cos(α+β)的值已知tan(π/4+α)=2,tanβ=1/2.⑴求tanα的值,⑵求sin(α+β)-2sinαcosβ/2sinαcosβ+cos(α+β)的值
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![已知tan(π/4+α)=2,tanβ=1/2.⑴求tanα的值,⑵求sin(α+β)-2sinαcosβ/2sinαcosβ+cos(α+β)的值已知tan(π/4+α)=2,tanβ=1/2.⑴求tanα的值,⑵求sin(α+β)-2sinαcosβ/2sinαcosβ+cos(α+β)的值](/uploads/image/z/2581791-15-1.jpg?t=%E5%B7%B2%E7%9F%A5tan%28%CF%80%2F4%2B%CE%B1%29%3D2%2Ctan%CE%B2%3D1%2F2.%E2%91%B4%E6%B1%82tan%CE%B1%E7%9A%84%E5%80%BC%2C%E2%91%B5%E6%B1%82sin%28%CE%B1%2B%CE%B2%29-2sin%CE%B1cos%CE%B2%2F2sin%CE%B1cos%CE%B2%2Bcos%28%CE%B1%2B%CE%B2%29%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5tan%28%CF%80%2F4%2B%CE%B1%29%3D2%2Ctan%CE%B2%3D1%2F2.%E2%91%B4%E6%B1%82tan%CE%B1%E7%9A%84%E5%80%BC%2C%E2%91%B5%E6%B1%82sin%28%CE%B1%2B%CE%B2%29-2sin%CE%B1cos%CE%B2%2F2sin%CE%B1cos%CE%B2%2Bcos%28%CE%B1%2B%CE%B2%29%E7%9A%84%E5%80%BC)
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