求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 23:11:21
![求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)](/uploads/image/z/2688974-62-4.jpg?t=%E6%B1%82lim%281%2B1%2Fn%2B2%29%3Dn-%3E0%E7%9A%84%E6%9E%81%E9%99%90%3F%EF%BC%88n%E8%B6%8B%E5%90%91%E6%97%A0%E7%A9%B7%E5%A4%A7%EF%BC%89)
x){)'3WPP?OH6Og_Μ`~OGދmO'L|6}۟.Y~OMR>yl(+K-P,mңy6yvPklCm~&a2Dl=~w/۟c"eNyCņE@Òh-0St
求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)
求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)
求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)
lim[1+1/(n+2)]=1+0=1
n→∞
lim(1+1/n+2)=lim1+lim(1/n)+lim2=1+0+2=3
希望你能采纳我的答案 谢谢
lim[(1+1)/(n+2)]=0
n→∞
求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)
若lim[(2n-1)an]=1 求lim(n*an)的值
求lim n→∞(1/n^2 + 2/n^2 +...+ n/n^2 )=lim n→∞ 1+2+...+n/n^2=lim n→∞ (1+n)n / 2n^2 这一步怎么来的?=1/2 lim n→∞(1+1/n) 这一步怎么来的?=1/2
求lim(n/(2n-1))的值
求 lim (n→+∞) n^( 1/n)的极限
lim[1+(1/n)]^n=e,则lim[(n+1)/n]^(2n+1)的值等于?e^2
lim[1+(1/n)]^n=e,则lim[n+(1/n)]^(2n+1)的值等于?e^2
求极限lim(√(n^2-1) -n)/(n-√(n^2+1))的值
lim((n^2+2n-1)/(2n^2-n+3))的值 求详解
求lim(n->无穷)(3n+5)/(n^2+n+4)^1/2的极限
求lim[ x^(n+1)-(n+1)x+n]/(x-1)^2 x-->1=lim(t->0) [ [ 1 + (n+1)t + (n+1)n/2t^2 + o(t^2)] -(n+1)-(n+1)t + n]/t^2?不懂
求极限n~∞,lim(n+1)/2n
求lim n→∞ (1+2/n)^n+3
求极限Lim((n-x)/(n+2))^(n+1)
lim (1+2/n)^n+4 n-->无穷大 求极限
lim(1-1/n)^(n^2)=?
lim(1-1/n^2)^n=?
求极限:lim(x→无穷)(2^n-7^n)/(2^n+7^n-1)=?