lim(x→0)[ln(1+x^2)]/[sin(1+x^2)]
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lim(x→0)[ln(1+x^2)]/[sin(1+x^2)]
lim(x→0)[ln(1+x^2)]/[sin(1+x^2)]
lim(x→0)[ln(1+x^2)]/[sin(1+x^2)]
分子为0,分母不为0,结果就是0
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