(x=0.5y=6.5)(x=1y=7.5)(x=1.5y=8.5)(x=2y=9.5)(x=2.5y=10.5)写出x与y的关系式急
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 10:33:10
x)Ө5353
+m͡,mTik eD
:4|ھɎZn~y=$\;ڹ֨BTF 1d kO
(x=0.5y=6.5)(x=1y=7.5)(x=1.5y=8.5)(x=2y=9.5)(x=2.5y=10.5)写出x与y的关系式急
(x=0.5y=6.5)(x=1y=7.5)(x=1.5y=8.5)(x=2y=9.5)(x=2.5y=10.5)写出x与y的关系式急
(x=0.5y=6.5)(x=1y=7.5)(x=1.5y=8.5)(x=2y=9.5)(x=2.5y=10.5)写出x与y的关系式急
y=2x+5.5
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
化简 x / y(x+y) - y / x(x+y) =
y'/y=1/x
x(x+y)(x-y)-y(y+x)(y-x)=(x-y)( )填空
y'-(1/x)y=xe^-x
mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}]
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
y=x(x
y(x+y)+(x-y)²-(x+y)(x-y),其中x=-1/3,y=3
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
x>=1,x-y
y=x-1(x
x+x+x+x+y+y+y=56
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=12
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值