log4(3)+log8(3) 怎么算的我知道（1/2）log2(3)+（1/3）log2(3) 但是下一步怎么算的↓（5/6）log2(3)

log4(3)+log8(3) 怎么算 log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的? log4(3)+log8(3) 怎么相加? (log4(3)+log8(3))*log3(2) log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 求(log3^2 + log9^2)×（log4^3 + log8^3)的值.请给出过程,谢谢! (log3^2 + log9^4)×(log4^3 + log8^3) (log3 2+log9 2)*(log4 3+log8 3)求值 计算log9(根号2)*[log4(3)+log8(3)] 化简(log4(3)+log8(3))(log3(2)+log9(2)) 计算:(log4 3+log8 3)×log9 √2=? 求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16) (log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?.. 利用对数的换底公式化简下列式子.(log4 3+log8 3)(log3 2+log9 2)我怎么查到两种啊.到底哪个是对的. log4(3)+log8(3) 怎么算的我知道（1/2）log2(3)+（1/3）log2(3) 但是下一步怎么算的↓（5/6）log2(3) (log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32) (log8^27)/(log4^9)的值 (log4-3+log8-3)(log3-2+log9-2)补充说明一下,log4-3就是以4为底3的对数一定一定要写清楚过程!