已知函数f(x)=alnx+bx^2在点(1,f(1))处的切线方程为x-y-1=0(1)求函数f(X)的表达式(2)g(x)=t/x-lnx(t∈R),求f(X)≥g(x)恒成立时,t的取值范围
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![已知函数f(x)=alnx+bx^2在点(1,f(1))处的切线方程为x-y-1=0(1)求函数f(X)的表达式(2)g(x)=t/x-lnx(t∈R),求f(X)≥g(x)恒成立时,t的取值范围](/uploads/image/z/3138104-56-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dalnx%2Bbx%5E2%E5%9C%A8%E7%82%B9%281%2Cf%281%29%29%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAx-y-1%3D0%EF%BC%881%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0f%28X%EF%BC%89%E7%9A%84%E8%A1%A8%E8%BE%BE%E5%BC%8F%EF%BC%882%EF%BC%89g%28x%29%3Dt%2Fx-lnx%28t%E2%88%88R%EF%BC%89%2C%E6%B1%82f%28X%29%E2%89%A5g%28x%29%E6%81%92%E6%88%90%E7%AB%8B%E6%97%B6%2Ct%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
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