如图所示,在等边三角形ABC重,点m、n分别在边ac、bc上,且am=cn,bm与an相交于点e,bd⊥an于点d,求证:be=2de
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![如图所示,在等边三角形ABC重,点m、n分别在边ac、bc上,且am=cn,bm与an相交于点e,bd⊥an于点d,求证:be=2de](/uploads/image/z/3140196-60-6.jpg?t=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E5%9C%A8%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E9%87%8D%2C%E7%82%B9m%E3%80%81n%E5%88%86%E5%88%AB%E5%9C%A8%E8%BE%B9ac%E3%80%81bc%E4%B8%8A%2C%E4%B8%94am%3Dcn%2Cbm%E4%B8%8Ean%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9e%2Cbd%E2%8A%A5an%E4%BA%8E%E7%82%B9d%2C%E6%B1%82%E8%AF%81%EF%BC%9Abe%3D2de)
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