如图所示,在△ABC中,AD为∠BAC的角平分线,EF⊥AD交BC的延长线于点M,交AB,AC于点E,F,则∠M=1/2(∠ACB—∠B),试说明理由 图不太清楚,凑合看吧
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![如图所示,在△ABC中,AD为∠BAC的角平分线,EF⊥AD交BC的延长线于点M,交AB,AC于点E,F,则∠M=1/2(∠ACB—∠B),试说明理由 图不太清楚,凑合看吧](/uploads/image/z/3142013-5-3.jpg?t=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAD%E4%B8%BA%E2%88%A0BAC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CEF%E2%8A%A5AD%E4%BA%A4BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8E%E7%82%B9M%2C%E4%BA%A4AB%2CAC%E4%BA%8E%E7%82%B9E%2CF%2C%E5%88%99%E2%88%A0M%3D1%2F2%28%E2%88%A0ACB%E2%80%94%E2%88%A0B%EF%BC%89%2C%E8%AF%95%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1+%E5%9B%BE%E4%B8%8D%E5%A4%AA%E6%B8%85%E6%A5%9A%2C%E5%87%91%E5%90%88%E7%9C%8B%E5%90%A7)
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