设{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3且数列〔an+1-an〕是等差数列,数列{bn-2}是等比数列1.求数列{an}和{bn}的通项公式 2是否存在k属于N使Ak-Bk属于(0,1/2)
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![设{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3且数列〔an+1-an〕是等差数列,数列{bn-2}是等比数列1.求数列{an}和{bn}的通项公式 2是否存在k属于N使Ak-Bk属于(0,1/2)](/uploads/image/z/3172368-48-8.jpg?t=%E8%AE%BE%EF%BD%9Ban%7D%E5%92%8C%EF%BD%9Bbn%7D%E6%BB%A1%E8%B6%B3a1%EF%BC%9Db1%EF%BC%9D6%2Ca2%EF%BC%9Db2%EF%BC%9D4%2Ca3%EF%BC%9Db3%EF%BC%9D3%E4%B8%94%E6%95%B0%E5%88%97%E3%80%94an%2B1%EF%BC%8Dan%E3%80%95%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%E6%95%B0%E5%88%97%EF%BD%9Bbn%EF%BC%8D2%EF%BD%9D%E6%98%AF%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%971.%E6%B1%82%E6%95%B0%E5%88%97%EF%BD%9Ban%7D%E5%92%8C%EF%BD%9Bbn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F+2%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8k%E5%B1%9E%E4%BA%8EN%E4%BD%BFAk%EF%BC%8DBk%E5%B1%9E%E4%BA%8E%EF%BC%880%2C1%2F2%EF%BC%89)
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