数列 极限 证明证明:若(1)y(n+1)>y(n)(2)lim yn->∞(3)lim(x(n+1)-x(n))/(y(n+1)-yn)存在那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn)

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 14:03:14
数列 极限 证明证明:若(1)y(n+1)>y(n)(2)lim yn->∞(3)lim(x(n+1)-x(n))/(y(n+1)-yn)存在那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn)
xTN@--&].ĨąHhL|JtJ] N"t{9wN6'ZH^#y^VΫVQgd F:^_ېD5? "u-kj`Pϝ+SXeIrXf*QOA*$R˨_IҦWjyPV@ڠKknx&iaً߫ 1.9&8:n侾zǶ@{ªL1 mZa ]Uq-6OĒ aa5%Ζ8oǁ{Eg*t\{pJVe%mae ՊN͟|7vćXΑY-ؼ w88:bM ׋Rïi+m3C}=.

数列 极限 证明证明:若(1)y(n+1)>y(n)(2)lim yn->∞(3)lim(x(n+1)-x(n))/(y(n+1)-yn)存在那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn)
数列 极限 证明
证明:若
(1)y(n+1)>y(n)
(2)lim yn->∞
(3)lim(x(n+1)-x(n))/(y(n+1)-yn)存在
那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn)

数列 极限 证明证明:若(1)y(n+1)>y(n)(2)lim yn->∞(3)lim(x(n+1)-x(n))/(y(n+1)-yn)存在那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn)
还是老样子,极限的定义,无限分有限+无限
lim(x(n+1)-x(n))/(y(n+1)-yn)存在
设lim(x(n+1)-x(n))/(y(n+1)-yn)=a
对于任意e>0,存在N使得,对n>N有
|(x(n+1)-x(n))/(y(n+1)-yn)-a|那么对于n>N,有
a-e<(x(n+1)-x(n))/(y(n+1)-yn)(a-e)(y(n+1)-yn)那么
(a-e)(y(N+2)-y(N+1))(a-e)(y(N+3)-y(N+2))...
(a-e)(y(n+1)-yn)相加有
(a-e)(y(n+1)-y(N+1))
|(x(n+1)-x(N+1))/(y(n+1)-y(N+1))-a|现在要转化xn/yn为含有上式的形式,并证明其极限
xn/yn - a=(xn-x(N+1))/(yn-y(N+1))* (yn-y(N+1))/yn+(x(N+1)-a*y(N+1))/yn 凑出上式
|xn/yn - a|<=e|1-y(N+1)/yn|+|(x(N+1)-a*y(N+1))/yn|<=e+|(x(N+1)-a*y(N+1))/yn|
存在N'>N使得对n>N'有
|(x(N+1)-a*y(N+1))/yn|那么对于任意e>0
有|xn/yn - a|<2e
那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn)