求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 06:00:34
![求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),](/uploads/image/z/3653583-15-3.jpg?t=%E6%B1%82%E6%9E%81%E9%99%90Y%3Dlim+%28xy%2B1%29%2Fx%5E4%2By%5E4%2C%E5%BD%93%EF%BC%88x%2Cy%EF%BC%89%E2%86%92%EF%BC%880%2C0%EF%BC%89%2C)
x){ټƗ3'Dd*hTTjjWęhWƙ<;
{:M
tl"}Pf3HH!hk q[gÓK1
57}1F 10ٌg3=WnGR ^
求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
lim xy+1=1
lim x^4+y^4,=0
所以lim (xy+1)/x^4+y^4=1/0=∞
明显是无穷
求极限lim(x,y)→(0,0) 3xy/(xy+4)^1/2-2
跪求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
求lim(x,y)~(0,1)1-xy/x^2+y^2的极限,要详解
求极限lim(x→1 y→2) (x²+y²)/xy
lim[1+sin(xy)]^(y/x)x趋于0 y趋于π,求极限
求下列各极限 lim(x,y)→(0,1) (2-xy)/(x^2+2y)
求极限. lim (x→0) [√ (xy+4) -2 ]/xy (y→0)lim (x→0)(y→0)[√ (xy+4) -2 ]/xy
求极限lim(x,y)→(+∞,+∞) [(xy)/(x^2+y^2)]^xy.求极限lim(x,y)→(+∞,+∞) [(xy)/(x^2+y^2)]^xy,
极限x趋于2 y趋于o lim 1-xy/x^2+y^2 =
求极限(工本高数)lim [2-(xy+4)^(1/2)]/xyx->0y->0证明函数f(x,y)=(x+y)/(x-y)在点(0,0)处的二重极限不存在。上题不用答了,
两重极限题 求 lim(x,y)→(0,0)(1+xy)^(1/(x+y))的极限求lim(x,y)→(0,0)(1+xy)^(1/(x+y))的极限答案是不存在 求详解
求极限lim(1-cosxy)/x²y²,xy都趋于0
求lim(x→0,y→0) ysin(1/xy)的极限
Lim [2-根号下(xy+4)]/xy,能不能令t=xy后带入求极限?(x,y)→(0,0)
求二元函数极限:(x,y)趋近于(2,-1/2)时lim(2+xy)^(1/(y+xy^2))
1.画出方程表示的曲面:z= -(√(x^2+y^2))2.证明极限lim [(x+y)/(x-y)]不存在x→0,y→03.求函数极限lim[(x+y)sin(1/x^2+y^2)],lim[(xy)/(√(xy+1))-1]x→0,y→0 x→0,y→0
求极限lim(x,y)→(0,0) [1-cos(xy)]/xy^2.求极限lim(x,y)→(0,0) [1-cos(xy)]/xy^2,麻烦写下过程