作业帮tan=3,π
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tan=3,π
tan=3,π
tan=3,π
(cosa-sina)^2=(cosa)^2+(sina)^2-2sinacosa=1-sin(2a)
sin2a=2tana/(1+tana)^2=6/4^2=3/8
(cos-sina)^2=5/8
π
tan=3,π
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利用正切函数单调性比较 函数值大小tan [(75/11)π]&tan [(-58/11)π]这样可不可以 下面算式有错吗tan[(75/11)π] = tan[(9/11)π] =tan[(1-2/11)π] = -tan 2/11 πtan [(-58/11)π] = tan [-(8/11)π] = -tan[(1-3/11)π] = tan 3/11 π
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已知tan(x-y)=2,tan(y+π/5)=3,则tan(x+π/5)等于
tan(α+β)=3/5,tan(β-π/4)=1/4,则tan(α+π/4)
若tanα=-1/3,tan(β-(π/4))=-1/3,则tan(α+β)=
已知 Tan x=根号3,π