1.如图,在三角形ABC中,AC=BC,D是AB的中点,点P是线段CD上在三角形ABC中,AB=AC,D是AB的中点,P是线段CD上不与端点重合的任意一点,连接AP交BC于点E,连接BP交AC于点F求证:(1)角CAE=角CBF; (2)AE=B
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![1.如图,在三角形ABC中,AC=BC,D是AB的中点,点P是线段CD上在三角形ABC中,AB=AC,D是AB的中点,P是线段CD上不与端点重合的任意一点,连接AP交BC于点E,连接BP交AC于点F求证:(1)角CAE=角CBF; (2)AE=B](/uploads/image/z/3717426-66-6.jpg?t=1.%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAC%3DBC%2CD%E6%98%AFAB%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E7%82%B9P%E6%98%AF%E7%BA%BF%E6%AE%B5CD%E4%B8%8A%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAB%3DAC%2CD%E6%98%AFAB%E7%9A%84%E4%B8%AD%E7%82%B9%2CP%E6%98%AF%E7%BA%BF%E6%AE%B5CD%E4%B8%8A%E4%B8%8D%E4%B8%8E%E7%AB%AF%E7%82%B9%E9%87%8D%E5%90%88%E7%9A%84%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9%2C%E8%BF%9E%E6%8E%A5AP%E4%BA%A4BC%E4%BA%8E%E7%82%B9E%2C%E8%BF%9E%E6%8E%A5BP%E4%BA%A4AC%E4%BA%8E%E7%82%B9F%E6%B1%82%E8%AF%81%EF%BC%9A%EF%BC%881%EF%BC%89%E8%A7%92CAE%3D%E8%A7%92CBF%3B++++++++++%EF%BC%882%EF%BC%89AE%3DB)
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