已知函数f(x)=p1nx+(p-1)x2+1.(1)讨论函数f(x)的单调性;(2)当P=1时,f(x)≤kx恒成立,求实数k的取值范围;(3)证明:1n(n+1)<1+ 1/ 2 + 1/ 3 +…+ 1/n (n∈N+).
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/17 06:42:43
![已知函数f(x)=p1nx+(p-1)x2+1.(1)讨论函数f(x)的单调性;(2)当P=1时,f(x)≤kx恒成立,求实数k的取值范围;(3)证明:1n(n+1)<1+ 1/ 2 + 1/ 3 +…+ 1/n (n∈N+).](/uploads/image/z/3737462-14-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dp1nx%2B%EF%BC%88p-1%EF%BC%89x2%2B1%EF%BC%8E%EF%BC%881%EF%BC%89%E8%AE%A8%E8%AE%BA%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%8D%95%E8%B0%83%E6%80%A7%EF%BC%9B%EF%BC%882%EF%BC%89%E5%BD%93P%3D1%E6%97%B6%2Cf%EF%BC%88x%EF%BC%89%E2%89%A4kx%E6%81%92%E6%88%90%E7%AB%8B%2C%E6%B1%82%E5%AE%9E%E6%95%B0k%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%9B%EF%BC%883%EF%BC%89%E8%AF%81%E6%98%8E%EF%BC%9A1n%EF%BC%88n%2B1%EF%BC%89%EF%BC%9C1%2B+1%2F+2+%2B+1%2F+3+%2B%E2%80%A6%2B+1%2Fn+%EF%BC%88n%E2%88%88N%2B%EF%BC%89%EF%BC%8E)
xUYOW+VT0/K_j֘7NUOf /
Ձb P(/ ν3~/oPWc]9;߹ߙ:,uо%p`}4
's2{^r]FWN^aUT_n˧T*=/q2~$*n@1 5o~
1xrZiklV"H꺖gB,B
\%v0"FW]fHJoys@&`%sR`(]CYtߝ#0@=O]Wb0n,!S> ^E:^!M80#[׃[\2̜W? []]q$B}/k