设函数fx=ax^2+bx+c 且f1=-a/2 3a>2c>2b 求证(1)a>0 且 -3<b设函数fx=ax^2+bx+c 且f1=-a/2 3a>2c>2b 求证(1)a>0 且 -3<b/a<-3/4 (2)函数fx在区间(0,2)内
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![设函数fx=ax^2+bx+c 且f1=-a/2 3a>2c>2b 求证(1)a>0 且 -3<b设函数fx=ax^2+bx+c 且f1=-a/2 3a>2c>2b 求证(1)a>0 且 -3<b/a<-3/4 (2)函数fx在区间(0,2)内](/uploads/image/z/3769997-5-7.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0fx%3Dax%5E2%2Bbx%2Bc+%E4%B8%94f1%3D-a%2F2+3a%EF%BC%9E2c%EF%BC%9E2b+%E6%B1%82%E8%AF%81%EF%BC%881%EF%BC%89a%EF%BC%9E0+%E4%B8%94+-3%EF%BC%9Cb%E8%AE%BE%E5%87%BD%E6%95%B0fx%3Dax%5E2%2Bbx%2Bc+%E4%B8%94f1%3D-a%2F2+3a%EF%BC%9E2c%EF%BC%9E2b+%E6%B1%82%E8%AF%81%EF%BC%881%EF%BC%89a%EF%BC%9E0+%E4%B8%94+-3%EF%BC%9Cb%2Fa%EF%BC%9C-3%2F4+%EF%BC%882%EF%BC%89%E5%87%BD%E6%95%B0fx%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%880%2C2%EF%BC%89%E5%86%85)
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