设函数y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
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设函数y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
设函数y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
设函数y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
2x + (12x^3)(dy/dx) +1 +2(dy/dx) =0
(dy/dx) (12y^3 +2) = -2x-1
(dy/dx)= (-2x-1) / (12y^3 +2)
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