已知ai≠0,(i=1,2,3,4,...2011,2012),满足|a1|/a1+|a2|/a2+|a3|/a3+...+|a2011|/a2011+|a2012|/a2012=1968,使直线y=aix+i(i=1,2,3,4,...2011,2012)的图像经过一,二,四象限的ai的概率是______?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/21 20:42:11
![已知ai≠0,(i=1,2,3,4,...2011,2012),满足|a1|/a1+|a2|/a2+|a3|/a3+...+|a2011|/a2011+|a2012|/a2012=1968,使直线y=aix+i(i=1,2,3,4,...2011,2012)的图像经过一,二,四象限的ai的概率是______?](/uploads/image/z/3981434-50-4.jpg?t=%E5%B7%B2%E7%9F%A5ai%E2%89%A00%2C%28i%3D1%2C2%2C3%2C4%2C...2011%2C2012%29%2C%E6%BB%A1%E8%B6%B3%7Ca1%7C%2Fa1%2B%7Ca2%7C%2Fa2%2B%7Ca3%7C%2Fa3%2B...%2B%7Ca2011%7C%2Fa2011%2B%7Ca2012%7C%2Fa2012%3D1968%2C%E4%BD%BF%E7%9B%B4%E7%BA%BFy%3Daix%2Bi%28i%3D1%2C2%2C3%2C4%2C...2011%2C2012%29%E7%9A%84%E5%9B%BE%E5%83%8F%E7%BB%8F%E8%BF%87%E4%B8%80%2C%E4%BA%8C%2C%E5%9B%9B%E8%B1%A1%E9%99%90%E7%9A%84ai%E7%9A%84%E6%A6%82%E7%8E%87%E6%98%AF______%3F)
已知ai≠0,(i=1,2,3,4,...2011,2012),满足|a1|/a1+|a2|/a2+|a3|/a3+...+|a2011|/a2011+|a2012|/a2012=1968,使直线y=aix+i(i=1,2,3,4,...2011,2012)的图像经过一,二,四象限的ai的概率是______?
已知ai≠0,(i=1,2,3,4,...2011,2012),满足|a1|/a1+|a2|/a2+|a3|/a3+...+|a2011|/a2011+|a2012|/a2012=1968,使直线y=aix+i(i=1,2,3,4,...2011,2012)的图像经过一,二,四象限的ai的概率是______?
已知ai≠0,(i=1,2,3,4,...2011,2012),满足|a1|/a1+|a2|/a2+|a3|/a3+...+|a2011|/a2011+|a2012|/a2012=1968,使直线y=aix+i(i=1,2,3,4,...2011,2012)的图像经过一,二,四象限的ai的概率是______?
因为|ai|/ai=1或-1
又因为:|a1|/a1+|a2|/a2+|a3|/a3+...+|a2011|/a2011+|a2012|/a2012=1968;
所以这2012组中,有22个取到-1;
y=aix+i过一,二,四象限,所以ai<0;所以概率为:22/2012=11/1006;
根据ai≠0(i=1,2,…,2012)满足
|a1|a1+
|a2|a2+
|a3|a3+…+
|a2011|a2011+
|a2012|a2012=1968,ai有22个是负数,1990个是正数,从而得到图象经过一、二、四象限的ai概率∵ai≠0(i=1,2,…,2012)满足|a1|a1+
|a2|a2+
|a3|a3+…+<...
全部展开
根据ai≠0(i=1,2,…,2012)满足
|a1|a1+
|a2|a2+
|a3|a3+…+
|a2011|a2011+
|a2012|a2012=1968,ai有22个是负数,1990个是正数,从而得到图象经过一、二、四象限的ai概率∵ai≠0(i=1,2,…,2012)满足|a1|a1+
|a2|a2+
|a3|a3+…+
|a2011|a2011+
|a2012|a2012=1968,
∴ai有22个是负数,1990个是正数,
∵ai<0时直线y=aix+i(i=1,2,…,2012)的图象经过一、二、四象限,
∴使直线y=aix+i(i=1,2,…,2012)的图象经过一、二、四象限的ai概率是222012=111006,
故答案为:111006,
收起