将梯形ABCD的腰AB沿AD平行,平移长度等于AD的长,则下列说法不正确的是( )(A)AB∥DE且AB=DE(B) DEF=∠B(C) AD∥EC且AD=EC(D) BC=AD+EC
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![将梯形ABCD的腰AB沿AD平行,平移长度等于AD的长,则下列说法不正确的是( )(A)AB∥DE且AB=DE(B) DEF=∠B(C) AD∥EC且AD=EC(D) BC=AD+EC](/uploads/image/z/3989535-15-5.jpg?t=%E5%B0%86%E6%A2%AF%E5%BD%A2ABCD%E7%9A%84%E8%85%B0AB%E6%B2%BFAD%E5%B9%B3%E8%A1%8C%2C%E5%B9%B3%E7%A7%BB%E9%95%BF%E5%BA%A6%E7%AD%89%E4%BA%8EAD%E7%9A%84%E9%95%BF%2C%E5%88%99%E4%B8%8B%E5%88%97%E8%AF%B4%E6%B3%95%E4%B8%8D%E6%AD%A3%E7%A1%AE%E7%9A%84%E6%98%AF%EF%BC%88+++++%EF%BC%89%EF%BC%88A%29AB%E2%88%A5DE%E4%B8%94AB%3DDE%28B%29+DEF%3D%E2%88%A0B%EF%BC%88C%EF%BC%89+AD%E2%88%A5EC%E4%B8%94AD%3DEC%EF%BC%88D%EF%BC%89+++BC%3DAD%2BEC)
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