cos(α-β/2)=-1/3 sin(α/2-β)=1/4 且270°<α<360°,90°<β<180°,求cos(α+β)/2的值cos(α-β/2)=-1/3 sin(α/2-β)=1/4 且270°<α<360°,90°<β<180°,求cos(α+β)/2的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 12:51:20
![cos(α-β/2)=-1/3 sin(α/2-β)=1/4 且270°<α<360°,90°<β<180°,求cos(α+β)/2的值cos(α-β/2)=-1/3 sin(α/2-β)=1/4 且270°<α<360°,90°<β<180°,求cos(α+β)/2的值](/uploads/image/z/4547058-42-8.jpg?t=cos%28%CE%B1-%CE%B2%2F2%29%3D-1%2F3+sin%EF%BC%88%CE%B1%2F2-%CE%B2%EF%BC%89%3D1%2F4+%E4%B8%94270%C2%B0%EF%BC%9C%CE%B1%EF%BC%9C360%C2%B0%2C90%C2%B0%EF%BC%9C%CE%B2%EF%BC%9C180%C2%B0%2C%E6%B1%82cos%EF%BC%88%CE%B1%2B%CE%B2%EF%BC%89%2F2%E7%9A%84%E5%80%BCcos%28%CE%B1-%CE%B2%2F2%29%3D-1%2F3+sin%EF%BC%88%CE%B1%2F2-%CE%B2%EF%BC%89%3D1%2F4+%E4%B8%94270%C2%B0%EF%BC%9C%CE%B1%EF%BC%9C360%C2%B0%2C90%C2%B0%EF%BC%9C%CE%B2%EF%BC%9C180%C2%B0%2C%E6%B1%82cos%EF%BC%88%CE%B1%2B%CE%B2%EF%BC%89%2F2%E7%9A%84%E5%80%BC)
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