1.已知函数f(x)=ae^x+(1/ae^x)+b(a>0)(1)求f(x)在[0,+∞)内最小值(2)设曲线y=f(x)在点(2,f(2))处切线方程为y=(3/2)x,求实数a,b的值
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![1.已知函数f(x)=ae^x+(1/ae^x)+b(a>0)(1)求f(x)在[0,+∞)内最小值(2)设曲线y=f(x)在点(2,f(2))处切线方程为y=(3/2)x,求实数a,b的值](/uploads/image/z/5223596-68-6.jpg?t=1.%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dae%5Ex%2B%EF%BC%881%2Fae%5Ex%EF%BC%89%2Bb%EF%BC%88a%EF%BC%9E0%EF%BC%89%EF%BC%881%EF%BC%89%E6%B1%82f%EF%BC%88x%EF%BC%89%E5%9C%A8%5B0%2C%2B%E2%88%9E%EF%BC%89%E5%86%85%E6%9C%80%E5%B0%8F%E5%80%BC%EF%BC%882%EF%BC%89%E8%AE%BE%E6%9B%B2%E7%BA%BFy%3Df%EF%BC%88x%EF%BC%89%E5%9C%A8%E7%82%B9%EF%BC%882%2Cf%EF%BC%882%EF%BC%89%EF%BC%89%E5%A4%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAy%3D%EF%BC%883%2F2%EF%BC%89x%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%2Cb%E7%9A%84%E5%80%BC)
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