函数y=cos^(x-π/12)+sin^2(x+π/12)-1的最小正周期为( )
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 14:28:18
![函数y=cos^(x-π/12)+sin^2(x+π/12)-1的最小正周期为( )](/uploads/image/z/5347137-57-7.jpg?t=%E5%87%BD%E6%95%B0y%3Dcos%5E%28x-%CF%80%2F12%29%2Bsin%5E2%28x%2B%CF%80%2F12%EF%BC%89-1%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%BA%EF%BC%88+%EF%BC%89)
x){ھ
q
434*{:u
jy6gk?ٜOvzC(kTOl&jʆ( fiU-,
44caºam0&d-
!t!.)ֆ7EЅ5 #[B (|BA
z6u0*0|~qAb(^
函数y=cos^(x-π/12)+sin^2(x+π/12)-1的最小正周期为( )
函数y=cos^(x-π/12)+sin^2(x+π/12)-1的最小正周期为( )
函数y=cos^(x-π/12)+sin^2(x+π/12)-1的最小正周期为( )
y=cos²(x-π/12)+sin²(x+π/12)-1
=½[1+cos(2x-π/6)]+½[1-cos(2x+π/6)]-1
=½[cos(2x-π/6)-cos(2x+π/6)]
=-½ * 2 sin[(2x-π/6+2x+π/6)/2] sin[(2x-π/6-2x-π/6)/2]
=sin2x sin(π/6)
=½sin2x
=½sin(2x+2kπ)
=½sin2(x+kπ) k为整数
最小正周期为π
函数y=(sin x+cos x)(sin x-cos x)是什么函数.还有单调性
函数y=sin(x)cos(x+ π/4)+cos(x)sin(x+π/4)的最小正周期是
函数y=sin x+cos x的最大值为
函数y=cos^2X-sin^2x最小值
函数y=sin(2x+α)cos(x+α)-cos(2x+α)sin(x+α)在x=π/3处的导函数为
求函数y=sin^4x+cos^4x,x(0,π/6)的最小值
函数y=cos(sin x)的值域为?
函数y=√cos(sin x)的定义域,
函数y=cos(sin x)值域为
函数y=sin²(x+π/12)+cos²(x-π/12)-1的周期T=?,奇偶性为
函数y=cos²(x-π/12)+sin²(x+π/12)-1的最小正周期
函数y=cos^(x-π/12)+sin^2(x+π/12)-1的最小正周期为( )
求函数y=sin²(x+π/12)+cos²(x-π/12)-1的最大值
函数y=2sin(x+π/12)cos(x+π/4)的最大值、最小值分别为
函数y=5sin(x+π/6)+12cos(x+π/6)的最大值最小值是
函数 y=3sinπx+根号7cosπx的最大值
函数y=sin(π/2+x)cos(π/6-x)的最大值为
求函数y = sin(x+π/6)-cos(x+π/3) 的最大值和最小值