在(0,2π)内,使得sinx>cosx成立的x的取值范围是A ( π/4,π/2)∪(π,5π/4) B(π/4,π)C ( π/4,5π/4) D(π/4,π)∪(5π/4,3π/2) 但我还是不理解.尽量通俗易懂最好这个我看不懂最佳答案sinx-cosx>0(根号2)sin(x-π
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![在(0,2π)内,使得sinx>cosx成立的x的取值范围是A ( π/4,π/2)∪(π,5π/4) B(π/4,π)C ( π/4,5π/4) D(π/4,π)∪(5π/4,3π/2) 但我还是不理解.尽量通俗易懂最好这个我看不懂最佳答案sinx-cosx>0(根号2)sin(x-π](/uploads/image/z/5351573-29-3.jpg?t=%E5%9C%A8%EF%BC%880%2C2%CF%80%EF%BC%89%E5%86%85%2C%E4%BD%BF%E5%BE%97sinx%3Ecosx%E6%88%90%E7%AB%8B%E7%9A%84x%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AFA+%EF%BC%88+%CF%80%2F4%2C%CF%80%2F2%29%E2%88%AA%28%CF%80%2C5%CF%80%2F4%29+B%28%CF%80%2F4%2C%CF%80%29C+%28+%CF%80%2F4%2C5%CF%80%2F4%29+D%28%CF%80%2F4%2C%CF%80%29%E2%88%AA%EF%BC%885%CF%80%2F4%2C3%CF%80%2F2%29+%E4%BD%86%E6%88%91%E8%BF%98%E6%98%AF%E4%B8%8D%E7%90%86%E8%A7%A3.%E5%B0%BD%E9%87%8F%E9%80%9A%E4%BF%97%E6%98%93%E6%87%82%E6%9C%80%E5%A5%BD%E8%BF%99%E4%B8%AA%E6%88%91%E7%9C%8B%E4%B8%8D%E6%87%82%E6%9C%80%E4%BD%B3%E7%AD%94%E6%A1%88sinx-cosx%3E0%28%E6%A0%B9%E5%8F%B72%29sin%28x-%CF%80)
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