∫sixcosx/1+sin^4x dx请你详解

∫sixcosx/1+sin^4x dx请你详解 ∫sinxcosx/(1+sin^4x)dx ∫1/sin^4x dx ∫sin(1/x)dx 求∫1/(sin^4x+cos^4x)dx, ∫[1/(sin^2(x)cos^4(x)]dx 求解∫1/(cos^4(x)sin^2(x))dx ∫ x sin(x+1) dx ∫sin（6x）sin（4x）dx ∫sin²x(1-sin²x)dx是多少? ∫sin^2x/(1+sin^2x )dx求解, ∫(tanx)^1/4 dx/sin^2x 求∫In[1/sin^4(x)]dx~不定积分啊~ ∫cosx/(1+4sin^2x)dx ∫sin^4 (x) dx 求不定积分 ∫ 4/sin^2x dx ∫(1-sin/x+cos)dx不定积分 ∫（1-sin^3x）dx