已知x∈[0,π/2],求函数y=cos(π/12 - x)-cos(5π/12 + x)的值域?已知函数f(x)=a*sinx+b*cosx,(ab≠0)的最大值是2,且f(π/6)=根号3.求f(π/3)化简:根号【1+sin10°】+根号【1-sin10°】
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![已知x∈[0,π/2],求函数y=cos(π/12 - x)-cos(5π/12 + x)的值域?已知函数f(x)=a*sinx+b*cosx,(ab≠0)的最大值是2,且f(π/6)=根号3.求f(π/3)化简:根号【1+sin10°】+根号【1-sin10°】](/uploads/image/z/5381020-28-0.jpg?t=%E5%B7%B2%E7%9F%A5x%E2%88%88%5B0%2C%CF%80%2F2%5D%2C%E6%B1%82%E5%87%BD%E6%95%B0y%3Dcos%EF%BC%88%CF%80%2F12+-+x%EF%BC%89-cos%EF%BC%885%CF%80%2F12+%2B+x%EF%BC%89%E7%9A%84%E5%80%BC%E5%9F%9F%3F%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Da%2Asinx%2Bb%2Acosx%2C%EF%BC%88ab%E2%89%A00%EF%BC%89%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E6%98%AF2%2C%E4%B8%94f%EF%BC%88%CF%80%2F6%29%3D%E6%A0%B9%E5%8F%B73.%E6%B1%82f%EF%BC%88%CF%80%2F3%29%E5%8C%96%E7%AE%80%3A%E6%A0%B9%E5%8F%B7%E3%80%901%2Bsin10%C2%B0%E3%80%91%2B%E6%A0%B9%E5%8F%B7%E3%80%901-sin10%C2%B0%E3%80%91)
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