∫1/1-cos x dx

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∫1/1-cos x dx
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∫1/1-cos x dx
∫1/1-cos x dx

∫1/1-cos x dx
原式=∫dx/(2sin²(x/2))
=1/2∫csc²(x/2)dx
=∫csc²(x/2)d(x/2)
=-cot(x/2)+C (C是积分常数).