1、若{An}满足An=n2+λn (λ∈ N*)为递增数列,求实数λ的取值范围.2、已知数列{An}满足2a1+2∧2a2+...+2∧n an=1/2(n∧2+3n)证明:数列{an}不是等比数列数列{an}前n项和为Sn,求证Sn<3(n∈ N*)
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![1、若{An}满足An=n2+λn (λ∈ N*)为递增数列,求实数λ的取值范围.2、已知数列{An}满足2a1+2∧2a2+...+2∧n an=1/2(n∧2+3n)证明:数列{an}不是等比数列数列{an}前n项和为Sn,求证Sn<3(n∈ N*)](/uploads/image/z/5401550-38-0.jpg?t=1%E3%80%81%E8%8B%A5%EF%BD%9BAn%EF%BD%9D%E6%BB%A1%E8%B6%B3An%3Dn2%2B%CE%BBn+%28%CE%BB%E2%88%88+N%2A%EF%BC%89%E4%B8%BA%E9%80%92%E5%A2%9E%E6%95%B0%E5%88%97%2C%E6%B1%82%E5%AE%9E%E6%95%B0%CE%BB%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4.2%E3%80%81%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%EF%BD%9BAn%EF%BD%9D%E6%BB%A1%E8%B6%B32a1%2B2%E2%88%A72a2%2B...%2B2%E2%88%A7n+an%3D1%EF%BC%8F2%28n%E2%88%A72%2B3n%29%E8%AF%81%E6%98%8E%EF%BC%9A%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E4%B8%8D%E6%98%AF%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E6%B1%82%E8%AF%81Sn%EF%BC%9C3%EF%BC%88n%E2%88%88+N%2A%29)
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1、若{An}满足An=n2+λn (λ∈ N*)为递增数列,求实数λ的取值范围.2、已知数列{An}满足2a1+2∧2a2+...+2∧n an=1/2(n∧2+3n)证明:数列{an}不是等比数列数列{an}前n项和为Sn,求证Sn<3(n∈ N*)
1、若{An}满足An=n2+λn (λ∈ N*)为递增数列,求实数λ的取值范围.
2、已知数列{An}满足2a1+2∧2a2+...+2∧n an=1/2(n∧2+3n)
证明:数列{an}不是等比数列
数列{an}前n项和为Sn,求证Sn<3(n∈ N*)
1、若{An}满足An=n2+λn (λ∈ N*)为递增数列,求实数λ的取值范围.2、已知数列{An}满足2a1+2∧2a2+...+2∧n an=1/2(n∧2+3n)证明:数列{an}不是等比数列数列{an}前n项和为Sn,求证Sn<3(n∈ N*)
我提示你下把,1.满足递增数列只要满足A(n+1)-A(n)>0就可以了,然后自己找范围
2.证明2a1=-2∧2a2-.
a1=-2∧2a2-.../2
同理求出a2然后a2/a1不等于一个数就证明出来了,或者用反证法,假设是等比数列然后再证明没有等比项也可以,具体没有细看
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