求,不定积分.∫上限兀/2 下限0(cosx/2-sinx/2)dx+∫上限 兀下限 兀/2(sinx/2-cosx/2)dx

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求,不定积分.∫上限兀/2 下限0(cosx/2-sinx/2)dx+∫上限 兀下限 兀/2(sinx/2-cosx/2)dx
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求,不定积分.∫上限兀/2 下限0(cosx/2-sinx/2)dx+∫上限 兀下限 兀/2(sinx/2-cosx/2)dx
求,不定积分.∫上限兀/2 下限0(cosx/2-sinx/2)dx+∫上限 兀下限 兀/2(sinx/2-cosx/2)dx

求,不定积分.∫上限兀/2 下限0(cosx/2-sinx/2)dx+∫上限 兀下限 兀/2(sinx/2-cosx/2)dx
∫(0,兀/2)(cosx/2-sinx/2)dx+∫(兀/2.兀)(sinx/2-cosx/2)dx
=2[∫(0,兀/2)(cosx/2-sinx/2)dx/2+∫(兀/2.兀)(sinx/2-cosx/2)dx/2 ]
=2(sinx/2+cosx/2)|(0,兀/2)-2(sinx/2+cosx/2)|(兀/2.兀)
=2(√2-1)-2(1-√2)
=4(√2-1)

这不是定积分吗?
clear all;clc;
syms x
y1=cos(x/2)-sin(x/2);
y2=sin(x/2)-cos(x/2);
jf=int(y1,0,pi/2)+int(y2,pi/2,pi)
jf =
4*2^(1/2)-4