sin²1°+sin²2°+sin²3°+…+sin²89°=?麻烦写下过程,

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sin²1°+sin²2°+sin²3°+…+sin²89°=?麻烦写下过程,
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sin²1°+sin²2°+sin²3°+…+sin²89°=?麻烦写下过程,
sin²1°+sin²2°+sin²3°+…+sin²89°=?麻烦写下过程,

sin²1°+sin²2°+sin²3°+…+sin²89°=?麻烦写下过程,

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答案：44又1/2

sin1=cos89
sin²1°+sin²89°=cos²89+sin²89=1
首尾累加
结果就是44+sin²45°=44又1/2

44.5
过程：先证明sin²a+sin²b=1，其中a+b=90°，sin²a+sin²b=sin²a+sin²（90°-a）=sin²a+cos²a=1.
所以原式=（sin²1°+sin²89°）+...+(sin²44°+sin²46°)+sin²45°=44.5

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