lim 2n-根号(3-an+4n^2)=1,则a为
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/02 10:07:01
x)U0}`ƺy&yqF:O;f&>ٱ&Hev6Dhkb_\g 6
lim 2n-根号(3-an+4n^2)=1,则a为
lim 2n-根号(3-an+4n^2)=1,则a为
lim 2n-根号(3-an+4n^2)=1,则a为
a=4
lim 2n-根号(3-an+4n^2)=1,则a为
1、lim n->无穷 根号[(n^4+n+1)-n^2]*(3n+4)
求1.lim(3n-(3n^2+2n)/(n-1)) 2.lim(8+1/(n+1)) 3.lim根号n(根号(n+1)-根号(n-3))
lim根号n^2+n+1/3n-2
lim根号n^2+n+1/3n-2=?
lim(根号(n平方+2n)-根号(n平方-1))
若lim (3n^2+5)An=2,且lim (1-n^2)An?
lim(n→∞) 根号n+2-根号n+1/根号n+1-根号n
lim(n+3)(4-n)/(n-1)(3-2n)
lim(n^3+n)/(n^4-3n^2+1)
lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b
已知liman=2求lim((n+an)/(n-an))
根式怎么有理化!lim(根号(n^2+n)-n)
1 lim[2n+1-根号(an^2+bn+1)]=2 求a b的值2 lim(-3)^(n+1)+a^(n+1)/(-3)^n-a^n
lim (n→+∞)(根号(n+2)-2*(根号n+1)+根号n)
lim(n→∞) 根号n+2(根号n+1-根号n-1)
lim(n→∞)(根号n+2-根号n)*根号n-1=?
数列极限的运算lim an/(an+1) =2 求lim 2anlim (2n+1)*an=3 求lim n*an