函数y=cos(x-π/8)(x∈[π/6,2π/3])的最小值是多少
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/20 01:32:23
x){ھ
-45*utDf:F@8VgsnڰٌOzaMR>%l(])X22yԹbahKc%dg[2p+n"';?Cѳ/.H̳z 2F&:P P` [Bj&>
函数y=cos(x-π/8)(x∈[π/6,2π/3])的最小值是多少
函数y=cos(x-π/8)(x∈[π/6,2π/3])的最小值是多少
函数y=cos(x-π/8)(x∈[π/6,2π/3])的最小值是多少
x∈[π/6,2π/3]
π/24≤x-π/8≤13π/24
7.5°到97.5°之间.
最小值就是cos97.5°,也即cos13π/24.
x∈[π/6,2π/3]
x-π/8∈[π/24,13π/24]
13π/24>12π/24=π/2
=>函数y=cos(x-π/8)(x∈[π/6,2π/3])的最小值是cos(13π/24)
函数y=cos(x-π/8)(x∈[π/6,2π/3]的最小值.
函数y=cos(x-π/8)(x∈【π/6.2π/3】)的最小值是
函数y=cos平方(x+π/4),x∈R是什么函数
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是:
函数y=cosπ/2x×cosπ/2(x-1)的最小正周期
函数y=cosπ/2x×cosπ/2(x-1)的最小正周期
化简函数y=cos^2(x+7π/12)-cos^2(x+π/12),
判断下列函数y=cos(x+π/3)cos(x-π/3)的奇偶性
函数y=cos^2(π/4-x)-cos^2(π/4+x)的值域是
函数y=cos(x-π/4)cos(x+π/4)的值域是?
求函数y=cos(πx)cosπ(x-1)的最小正周期?
函数y=2cos(x-π/3)(π/6
求函数y=cos(x-π/3),x∈[-π/2,π/2]的值域,
函数y=cos(x+π/3)的值域(其中x∈[-π/2,π/3])
函数y=cos(x-π/6)(x∈【π/6,2π/3】)的最小值
函数y=cos(x-π/6)(x∈[π/6,2π/3]的最小值.
函数y=3cos(-2x+π/4)x∈[-π,π]的减区间