若x满足不等式2(log0.5x)∧2+7log0.5x+3≤0,则f(x)=log0.5(x/2)log0.5(x/4)的最值?
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![若x满足不等式2(log0.5x)∧2+7log0.5x+3≤0,则f(x)=log0.5(x/2)log0.5(x/4)的最值?](/uploads/image/z/5515879-31-9.jpg?t=%E8%8B%A5x%E6%BB%A1%E8%B6%B3%E4%B8%8D%E7%AD%89%E5%BC%8F2%28log0.5x%29%E2%88%A72%2B7log0.5x%2B3%E2%89%A40%2C%E5%88%99f%28x%29%3Dlog0.5%28x%2F2%29log0.5%28x%2F4%29%E7%9A%84%E6%9C%80%E5%80%BC%3F)
若x满足不等式2(log0.5x)∧2+7log0.5x+3≤0,则f(x)=log0.5(x/2)log0.5(x/4)的最值?
若x满足不等式2(log0.5x)∧2+7log0.5x+3≤0,则f(x)=log0.5(x/2)log0.5(x/4)的最值?
若x满足不等式2(log0.5x)∧2+7log0.5x+3≤0,则f(x)=log0.5(x/2)log0.5(x/4)的最值?
2(log0.5x)∧2+7log0.5x+3≤0
[2(log0.5x)+1]*[(log0.5x)+3]≤0
-3≤(log0.5x)≤-1/2
log0.5(x/2)log0.5(x/4)=[(log0.5x)+1]*[(log0.5x)+2]=(log0.5x)∧2+3log0.5x+2
1/4≤(log0.5x)∧2+3log0.5x+2≤2
f(x)=log0.5(x/2)log0.5(x/4)的最小值是1/4,最大值是2.
∵在圆柱形水管的截面圆O中,OF是圆O的半径,直线CP切圆O于点C、P
∴OF垂直并平分CP ∵连接OC、OP,OC=OP=R
∴则Rt△OCG的高OG=OF-GF=R-2 ∴R=√(R-2)²+(20/2)²=26
∵连接OA、OB,OA=OB=R ∴则Rt△OEA的高OE=OF-GF-EG=...
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∵在圆柱形水管的截面圆O中,OF是圆O的半径,直线CP切圆O于点C、P
∴OF垂直并平分CP ∵连接OC、OP,OC=OP=R
∴则Rt△OCG的高OG=OF-GF=R-2 ∴R=√(R-2)²+(20/2)²=26
∵连接OA、OB,OA=OB=R ∴则Rt△OEA的高OE=OF-GF-EG=R-4=26-4=22
∴AE=√(OA²-OE²)=26²-22²=8√3 ∴AB=8√3×2=16√3
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