① 函数y=kx+3在定义域R上减函数 则A.k>0 B.k<0 C.k=0 D.k∈0① 函数y=kx+3在定义域R上减函数 则A.k>0 B.k<0 C.k=0 D.k∈0② 设函数f(x)在区间(-4,-1)上是减函数 则f(-3)___f(-2) (填 >或 <)③ 设函数f(x
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![① 函数y=kx+3在定义域R上减函数 则A.k>0 B.k<0 C.k=0 D.k∈0① 函数y=kx+3在定义域R上减函数 则A.k>0 B.k<0 C.k=0 D.k∈0② 设函数f(x)在区间(-4,-1)上是减函数 则f(-3)___f(-2) (填 >或 <)③ 设函数f(x](/uploads/image/z/5540309-53-9.jpg?t=%E2%91%A0+%E5%87%BD%E6%95%B0y%3Dkx%2B3%E5%9C%A8%E5%AE%9A%E4%B9%89%E5%9F%9FR%E4%B8%8A%E5%87%8F%E5%87%BD%E6%95%B0+%E5%88%99A.k%EF%BC%9E0+B.k%EF%BC%9C0+C.k%3D0+D.k%E2%88%880%E2%91%A0+%E5%87%BD%E6%95%B0y%3Dkx%2B3%E5%9C%A8%E5%AE%9A%E4%B9%89%E5%9F%9FR%E4%B8%8A%E5%87%8F%E5%87%BD%E6%95%B0+%E5%88%99A.k%EF%BC%9E0+B.k%EF%BC%9C0+C.k%3D0+D.k%E2%88%880%E2%91%A1+%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%88-4%2C-1%EF%BC%89%E4%B8%8A%E6%98%AF%E5%87%8F%E5%87%BD%E6%95%B0+%E5%88%99f%28-3%29___f%28-2%29+%28%E5%A1%AB+%EF%BC%9E%E6%88%96+%EF%BC%9C%29%E2%91%A2+%E8%AE%BE%E5%87%BD%E6%95%B0f%28x)
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