a+24=b,(b+3)除以(a+3)=3,求a、b值

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a+24=b,(b+3)除以(a+3)=3,求a、b值
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a+24=b,(b+3)除以(a+3)=3,求a、b值
a+24=b,(b+3)除以(a+3)=3,求a、b值

a+24=b,(b+3)除以(a+3)=3,求a、b值

a+24=b代入(b+3)除以(a+3)=3
得 (a+24+3)=3(a+3)
a+27=3a+9
a-3a=9-27
-2a=-18
a=9
b=33