证明:直角三角形的内切圆的圆心到三边的距离相等其实就是证明:三角形ABC是以C为直角的直角三角形,圆O是三角形的内切三角形,圆周与AC交于点M,与BC交于点N.证明:以C、O、M、N为顶点的四
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 18:32:50
![证明:直角三角形的内切圆的圆心到三边的距离相等其实就是证明:三角形ABC是以C为直角的直角三角形,圆O是三角形的内切三角形,圆周与AC交于点M,与BC交于点N.证明:以C、O、M、N为顶点的四](/uploads/image/z/5581594-10-4.jpg?t=%E8%AF%81%E6%98%8E%EF%BC%9A%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%86%85%E5%88%87%E5%9C%86%E7%9A%84%E5%9C%86%E5%BF%83%E5%88%B0%E4%B8%89%E8%BE%B9%E7%9A%84%E8%B7%9D%E7%A6%BB%E7%9B%B8%E7%AD%89%E5%85%B6%E5%AE%9E%E5%B0%B1%E6%98%AF%E8%AF%81%E6%98%8E%EF%BC%9A%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E6%98%AF%E4%BB%A5C%E4%B8%BA%E7%9B%B4%E8%A7%92%E7%9A%84%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E5%9C%86O%E6%98%AF%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%86%85%E5%88%87%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E5%9C%86%E5%91%A8%E4%B8%8EAC%E4%BA%A4%E4%BA%8E%E7%82%B9M%2C%E4%B8%8EBC%E4%BA%A4%E4%BA%8E%E7%82%B9N.%E8%AF%81%E6%98%8E%EF%BC%9A%E4%BB%A5C%E3%80%81O%E3%80%81M%E3%80%81N%E4%B8%BA%E9%A1%B6%E7%82%B9%E7%9A%84%E5%9B%9B)
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