设集合S={a0,a1,a2,a3},在S上定义运算.设集合S={a0,a1,a2,a3},在S上定义运算:ai@aj=ak(i,j,k为下标,@为新定义运算符号),其中k为i+j被4整除的余数,i,j=0、1、2、3,则求满足关系式(x@x)@a2=a0的x(x属于
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![设集合S={a0,a1,a2,a3},在S上定义运算.设集合S={a0,a1,a2,a3},在S上定义运算:ai@aj=ak(i,j,k为下标,@为新定义运算符号),其中k为i+j被4整除的余数,i,j=0、1、2、3,则求满足关系式(x@x)@a2=a0的x(x属于](/uploads/image/z/5587891-43-1.jpg?t=%E8%AE%BE%E9%9B%86%E5%90%88S%3D%EF%BD%9Ba0%2Ca1%2Ca2%2Ca3%EF%BD%9D%2C%E5%9C%A8S%E4%B8%8A%E5%AE%9A%E4%B9%89%E8%BF%90%E7%AE%97.%E8%AE%BE%E9%9B%86%E5%90%88S%3D%EF%BD%9Ba0%2Ca1%2Ca2%2Ca3%EF%BD%9D%2C%E5%9C%A8S%E4%B8%8A%E5%AE%9A%E4%B9%89%E8%BF%90%E7%AE%97%EF%BC%9Aai%40aj%3Dak%28i%2Cj%2Ck%E4%B8%BA%E4%B8%8B%E6%A0%87%2C%40%E4%B8%BA%E6%96%B0%E5%AE%9A%E4%B9%89%E8%BF%90%E7%AE%97%E7%AC%A6%E5%8F%B7%EF%BC%89%2C%E5%85%B6%E4%B8%ADk%E4%B8%BAi%2Bj%E8%A2%AB4%E6%95%B4%E9%99%A4%E7%9A%84%E4%BD%99%E6%95%B0%2Ci%2Cj%3D0%E3%80%811%E3%80%812%E3%80%813%2C%E5%88%99%E6%B1%82%E6%BB%A1%E8%B6%B3%E5%85%B3%E7%B3%BB%E5%BC%8F%EF%BC%88x%40x%29%40a2%3Da0%E7%9A%84x%28x%E5%B1%9E%E4%BA%8E)
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