设实数x,y满足x-y-2≥0,x+2y-4≥0,2y-3≤0(1)2x+y的最小值为
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设实数x,y满足x-y-2≥0,x+2y-4≥0,2y-3≤0(1)2x+y的最小值为
设实数x,y满足x-y-2≥0,x+2y-4≥0,2y-3≤0(1)2x+y的最小值为
设实数x,y满足x-y-2≥0,x+2y-4≥0,2y-3≤0(1)2x+y的最小值为
由(1)+(2)得:2x+y≥6
由式(3)解得y≤3/2
由式(1)解得x≥y+2 联合式(1)、(3)得 x≥7/2
由式(2)解得x≥4-2y 联合式(2)、(3)得 x≥1
故:x≥7/2
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