在四边行ABCD中,∠ABC=∠DCB,DA、CB的延长线交于P,求证PA*PD=PB*PC+AB*CD各位能者过来帮一下小妹呀,这道题目我解了两天两夜了,在线等候你的回答,可以画出一来的啊,例如先作等腰三角形EBC,在EC
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![在四边行ABCD中,∠ABC=∠DCB,DA、CB的延长线交于P,求证PA*PD=PB*PC+AB*CD各位能者过来帮一下小妹呀,这道题目我解了两天两夜了,在线等候你的回答,可以画出一来的啊,例如先作等腰三角形EBC,在EC](/uploads/image/z/6092584-16-4.jpg?t=%E5%9C%A8%E5%9B%9B%E8%BE%B9%E8%A1%8CABCD%E4%B8%AD%2C%E2%88%A0ABC%3D%E2%88%A0DCB%2CDA%E3%80%81CB%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E4%BA%8EP%2C%E6%B1%82%E8%AF%81PA%2APD%3DPB%2APC%2BAB%2ACD%E5%90%84%E4%BD%8D%E8%83%BD%E8%80%85%E8%BF%87%E6%9D%A5%E5%B8%AE%E4%B8%80%E4%B8%8B%E5%B0%8F%E5%A6%B9%E5%91%80%2C%E8%BF%99%E9%81%93%E9%A2%98%E7%9B%AE%E6%88%91%E8%A7%A3%E4%BA%86%E4%B8%A4%E5%A4%A9%E4%B8%A4%E5%A4%9C%E4%BA%86%2C%E5%9C%A8%E7%BA%BF%E7%AD%89%E5%80%99%E4%BD%A0%E7%9A%84%E5%9B%9E%E7%AD%94%2C%E5%8F%AF%E4%BB%A5%E7%94%BB%E5%87%BA%E4%B8%80%E6%9D%A5%E7%9A%84%E5%95%8A%EF%BC%8C%E4%BE%8B%E5%A6%82%E5%85%88%E4%BD%9C%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2EBC%EF%BC%8C%E5%9C%A8EC)
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