如图,在直三棱柱ABC-A1B1C1中,AC⊥BC,AC=BC=CC1,M、N分别是A1B、B1C1的中点.(Ⅰ)求证:MN⊥平面A1BC;(Ⅱ)求直线BC1和平面A1BC所成角的大小.用空间坐标系怎么解?第二问A1BC的法向量怎么求
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![如图,在直三棱柱ABC-A1B1C1中,AC⊥BC,AC=BC=CC1,M、N分别是A1B、B1C1的中点.(Ⅰ)求证:MN⊥平面A1BC;(Ⅱ)求直线BC1和平面A1BC所成角的大小.用空间坐标系怎么解?第二问A1BC的法向量怎么求](/uploads/image/z/6139368-0-8.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%9B%B4%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD%2CAC%E2%8A%A5BC%2CAC%3DBC%3DCC1%2CM%E3%80%81N%E5%88%86%E5%88%AB%E6%98%AFA1B%E3%80%81B1C1%E7%9A%84%E4%B8%AD%E7%82%B9%EF%BC%8E%EF%BC%88%E2%85%A0%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9AMN%E2%8A%A5%E5%B9%B3%E9%9D%A2A1BC%EF%BC%9B%EF%BC%88%E2%85%A1%EF%BC%89%E6%B1%82%E7%9B%B4%E7%BA%BFBC1%E5%92%8C%E5%B9%B3%E9%9D%A2A1BC%E6%89%80%E6%88%90%E8%A7%92%E7%9A%84%E5%A4%A7%E5%B0%8F%EF%BC%8E%E7%94%A8%E7%A9%BA%E9%97%B4%E5%9D%90%E6%A0%87%E7%B3%BB%E6%80%8E%E4%B9%88%E8%A7%A3%3F%E7%AC%AC%E4%BA%8C%E9%97%AEA1BC%E7%9A%84%E6%B3%95%E5%90%91%E9%87%8F%E6%80%8E%E4%B9%88%E6%B1%82)
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