关于二元函数极值,B^2-AC=0时,如何判断?比如,z=x^4+y^4;z'x=4x^3 ,z'y=4y^3 ,稳定点为(0,0)A=z''xx=12x^2,B=z''xy=0,C=z''yy=12y^2B^2-AC=0……如何破
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![关于二元函数极值,B^2-AC=0时,如何判断?比如,z=x^4+y^4;z'x=4x^3 ,z'y=4y^3 ,稳定点为(0,0)A=z''xx=12x^2,B=z''xy=0,C=z''yy=12y^2B^2-AC=0……如何破](/uploads/image/z/6615848-56-8.jpg?t=%E5%85%B3%E4%BA%8E%E4%BA%8C%E5%85%83%E5%87%BD%E6%95%B0%E6%9E%81%E5%80%BC%2CB%5E2-AC%3D0%E6%97%B6%2C%E5%A6%82%E4%BD%95%E5%88%A4%E6%96%AD%3F%E6%AF%94%E5%A6%82%2Cz%3Dx%5E4%2By%5E4%3Bz%27x%3D4x%5E3+%2Cz%27y%3D4y%5E3+%2C%E7%A8%B3%E5%AE%9A%E7%82%B9%E4%B8%BA%280%2C0%29A%3Dz%27%27xx%3D12x%5E2%2CB%3Dz%27%27xy%3D0%2CC%3Dz%27%27yy%3D12y%5E2B%5E2-AC%3D0%E2%80%A6%E2%80%A6%E5%A6%82%E4%BD%95%E7%A0%B4)
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