作业帮sinα^2+sin(120°-α)^2怎么化简
来源：学生作业帮助网 编辑：作业帮 时间：2024/10/02 19:06:02
x)+;1HHk ڠ{nfѳ';;L{&H(uv6h,nF2 mf`8#pe&`E@ LH ] S ,V noc `<,L= @!s6ԆVkSgo@!4jb@Am3M<;P Vخ
sinα^2+sin(120°-α)^2怎么化简
sinα^2+sin(120°-α)^2怎么化简
sinα^2+sin(120°-α)^2怎么化简
sinα^2+sin(120°-α)^2=sinα^2+sin(60°+α)^2=sinα^2+[sin60cosα+cos60sinα]^2
=sinα^2+(3/4cosα^2+1/4sinα^2+2*sin60*cos60*sinα*cosα)
=1/2sinα^2+(3/4cosα^2+3/4sinα^2)+sin60sinαcosα
=1/4（1-cos2α）+1+1/2sin60sin2α
=5/4+1/2(sin60sin2α-1/2cos2α)
=5/4-1/2cos(2α+60)
sin(α+β)-2sinαcosβ/2sinαsinβ+cos(α+β)
求证:sin(2α+β)/sinα-2cos(α+β)=sinβ/sinα
求证sin(2α+β)/sinα-2cos(α+β)=sinβ/sinα
求证sin(2α+β)/sinα-2cos(α+β)=sinβ/sinα
求证sin(2α+β)/sinα-2cos(α+β)=sinβ/sinα
证明：sin(2α+β)/sinα - 2cos(α+β)=sinβ/sinα
化简sin^2α+sin^2β+2sinαsinβcos(α+β)
化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)=
sin(α+β)sin(α-β)=sin^2α-sin^2β的推导过程
若sin^2β-sin^2α=m,则sin(α+β)sin(α-β)
(1-cos-sin)(1-sin+cos)/sin^2α-sinα
化简sin(α+β)-2sinαsinβ/2sinαsinβ+cos(α+β)
求证：sin²α+sin²β+2sinαsinβcos(α+β)=sin²(α+β)
证明(sinα)^2+(sin(120°-α))^2-2sinαsin（120°-α）cos60°=(sin60°)^2证明(sinα)^2+(sin(120°-α))^2-2sinαsin（120°-α）cos60°=(sin60°)^2
sinα^2+sin(120°-α)^2怎么化简
sinα-2cosα分之sinα+cosα
求证：sin^2(α+30°)+sin^2(α-30°)-sin^2α=定值
化简sin²α-2sinαcosα+1